Skip to main content

UPSEE 2020 Eligibility Criteria

 UPSEE is a state-level exam for candidates seeking admission in various UG and PG courses.

amropamgyan.blogspot.com|amropam gyan

Uttar Pradesh State Entrance Examination is a gateway to institutes affiliated to AKTU (earlier known as UPTU or Uttar Pradesh Technical University). The university also conducts PG level management exam for students who are seeking to enroll in the same. 

UPSEE 2020 Eligibility Criteria

Dr APJ Abdul Kalam Technical University has set certain standards for admission of students who wish to appear for UPSEE 2020 entrance examination. In case any student fails to fulfill the mentioned eligibility criteria and still appears in the examination, he/she might lose the candidature at any stage of the process of examination.



Different parameters that are expected to be fulfilled are listed below course-wise.

Course                                                                                 Eligibility Criteria

B.Tech/B.Pharma/B.Arch/BHMCT/BFAD/BFA         Intermediate Passed or equivalent

B.Tech (Lateral Entry)                                               B.Sc degree holder or Diploma holder

B. Pharmacy (Lateral Entry)                                       Diploma holder in Pharmacy

MCA (Lateral Entry)                                      BCA, B.Sc., (IT/Computer Science) degree holder

MBA/MCA                                                               B.Sc. Degree holder or equivalent

MAM                                                                       Intermediate Passed or Equivalent



Labels:

Comments

Post a Comment

Popular posts from this blog

NTA Declares JEE (Main)-2021 (February Session) NTA Scores for Paper 1 (B.E./B.Tech.) | JEE Mains 2021

The JEE (Main) Examination for B.E./B.Tech. was conducted by NTA from 24 to 26 February 2021. A total number of 6.52 lacs candidates were registered for Paper 1 (B.E. /B. Tech.) in this examination.  The Examination was conducted in 331 Cities [including 9 cities outside India in Colombo, Doha, Dubai, Kathmandu, Muscat, Riyadh, Sharjah, Singapore, and Kuwait] in 828 Centres.  A total number of 742 Observers, 261 City-Coordinators, 19 Regional Coordinators, 06 Special Coordinators & 02 National Coordinators were deployed at these centres to oversee the smooth and fair conduct of the examination.  The examination for Paper 1 (B.E. /B. Tech.) was conducted in a total of 6 shifts from 24 to 26 February 2021. The scores of Paper 1 (B.E./B.Tech.) are being declared today.   The Examination was conducted for the first time in 13 languages (English, Hindi, Gujarati along with Assamese, Bengali, Kannada, Malayalam, Marathi, Odia, Punjabi, Tamil, Telugu, and Urdu).  T...
Post a Comment
Read more

CSAB Special round for NITs, IIITs and CFTIS 2018

CSAB Special round for NITs, IIITs and CFTIS 2 018 After the  seat allotment of JoSAA 2018  is completed, CSAB will conduct a special round of counselling for NITs, IIITs and CFTIs through CSAB. The allotment will be open only for those candidates who have successfully completed their  JEE Main 2018   examination and secured valid scores. Exclusive:   JoSAA Counselling 2021, Documents Required... CSAB 2018 Special Round 1 Seat Allotment Result CSAB 2018 Special Round 1 Opening and Closing Rank Important Dates of CSAB Special round for NITs, IIITs and CFTIS 2018 S.No Events Important Dates (Tentative) 1 Registration and Choice Filling Fourth week of July 2018 2 Announcement of Seat Allotment Fourth week of July 2018 3 Reporting to Allotted Institutes First week of August 2018 click here to get full schedule... Eligibility Criteria of CSAB Special round ...
10 comments
Read more

Print Permutations

 1. You are given a string str. 2. Complete the body of printPermutations function - without changing signature - to calculate and print all permutations of str. Use sample input and output to take idea about permutations. Note -> The online judge can't force you to write the function recursively but that is what the spirit of question is. Write recursive and not iterative logic. The purpose of the question is to aid learning recursion and not test you. Input Format A string str Output Format Permutations of str in order hinted by Sample output Constraints 0 <= str.length <= 7 Sample Input abc Sample Output abc acb bac bca cab cba Solution: import java.io.*; import java.util.*; public class Main {     public static void main(String[] args) throws Exception {         Scanner sc = new Scanner(System.in);         String str = sc.nextLine();         printPermutations(str,"");     }     pu...
Post a Comment
Read more