Skip to main content

Programming using Java Hands On - Control Structures | Highest Placement

 

Highest Placement

SRV college wants to recognize the department which has succeeded in getting the maximum number of placements for this academic year. The departments that have participated in the recruitment drive are CSE,ECE, MECH. Help the college find the department getting maximum placements. Check for all the possible output given in the sample snapshot

Note : If any input is negative, the output should be "Input is invalid".  If all department has equal number of placements, the output should be "None of the department has got the highest placement".

Sample Input 1:

Enter the no of students placed in CSE:90
Enter the no of students placed in ECE:45
Enter the no of students placed in MECH:70
Sample Output 1:
Highest placement
CSE

Sample Input 2:
Enter the no of students placed in CSE:55
Enter the no of students placed in ECE:85
Enter the no of students placed in MECH:85
Sample Output 2:
Highest placement
ECE
MECH

Sample Input 3:
Enter the no of students placed in CSE:0
Enter the no of students placed in ECE:0
Enter the no of students placed in MECH:0
Sample Output 3:
None of the department has got the highest placement


Sample Input 4:
Enter the no of students placed in CSE:10
Enter the no of students placed in ECE:-50
Enter the no of students placed in MECH:40
Sample Output 4:
Input is Invalid 


Highest Placement SRV college wants to recognize the department which has succeeded in getting the maximum number of placements for this academic year. The departments that have participated in the recruitment drive are CSE,ECE, MECH. Help the college find the department getting maximum placements. Check for all the possible output given in the sample snapshot Note : If any input is negative, the output should be "Input is invalid". If all department has equal number of placements, the output should be "None of the department has got the highest placement". Sample Input 1: Enter the no of students placed in CSE:90 Enter the no of students placed in ECE:45 Enter the no of students placed in MECH:70 Sample Output 1: Highest placement CSE Sample Input 2: Enter the no of students placed in CSE:55 Enter the no of students placed in ECE:85 Enter the no of students placed in MECH:85 Sample Output 2: Highest placement ECE MECH Sample Input 3: Enter the no of students placed in CSE:0 Enter the no of students placed in ECE:0 Enter the no of students placed in MECH:0 Sample Output 3: None of the department has got the highest placement Sample Input 4: Enter the no of students placed in CSE:10 Enter the no of students placed in ECE:-50 Enter the no of students placed in MECH:40 Sample Output 4: Input is Invalid

 
Result Description
Summary of tests
 *Note: All the test cases might not have same weightage
+------------------------------+
|  7 tests run/ 7 tests passed |
+------------------------------+

Labels:

Comments

Post a Comment

Popular posts from this blog

NTA Declares JEE (Main)-2021 (February Session) NTA Scores for Paper 1 (B.E./B.Tech.) | JEE Mains 2021

The JEE (Main) Examination for B.E./B.Tech. was conducted by NTA from 24 to 26 February 2021. A total number of 6.52 lacs candidates were registered for Paper 1 (B.E. /B. Tech.) in this examination.  The Examination was conducted in 331 Cities [including 9 cities outside India in Colombo, Doha, Dubai, Kathmandu, Muscat, Riyadh, Sharjah, Singapore, and Kuwait] in 828 Centres.  A total number of 742 Observers, 261 City-Coordinators, 19 Regional Coordinators, 06 Special Coordinators & 02 National Coordinators were deployed at these centres to oversee the smooth and fair conduct of the examination.  The examination for Paper 1 (B.E. /B. Tech.) was conducted in a total of 6 shifts from 24 to 26 February 2021. The scores of Paper 1 (B.E./B.Tech.) are being declared today.   The Examination was conducted for the first time in 13 languages (English, Hindi, Gujarati along with Assamese, Bengali, Kannada, Malayalam, Marathi, Odia, Punjabi, Tamil, Telugu, and Urdu).  T...
Post a Comment
Read more

CSAB Special round for NITs, IIITs and CFTIS 2018

CSAB Special round for NITs, IIITs and CFTIS 2 018 After the  seat allotment of JoSAA 2018  is completed, CSAB will conduct a special round of counselling for NITs, IIITs and CFTIs through CSAB. The allotment will be open only for those candidates who have successfully completed their  JEE Main 2018   examination and secured valid scores. Exclusive:   JoSAA Counselling 2021, Documents Required... CSAB 2018 Special Round 1 Seat Allotment Result CSAB 2018 Special Round 1 Opening and Closing Rank Important Dates of CSAB Special round for NITs, IIITs and CFTIS 2018 S.No Events Important Dates (Tentative) 1 Registration and Choice Filling Fourth week of July 2018 2 Announcement of Seat Allotment Fourth week of July 2018 3 Reporting to Allotted Institutes First week of August 2018 click here to get full schedule... Eligibility Criteria of CSAB Special round ...
10 comments
Read more

Print Permutations

 1. You are given a string str. 2. Complete the body of printPermutations function - without changing signature - to calculate and print all permutations of str. Use sample input and output to take idea about permutations. Note -> The online judge can't force you to write the function recursively but that is what the spirit of question is. Write recursive and not iterative logic. The purpose of the question is to aid learning recursion and not test you. Input Format A string str Output Format Permutations of str in order hinted by Sample output Constraints 0 <= str.length <= 7 Sample Input abc Sample Output abc acb bac bca cab cba Solution: import java.io.*; import java.util.*; public class Main {     public static void main(String[] args) throws Exception {         Scanner sc = new Scanner(System.in);         String str = sc.nextLine();         printPermutations(str,"");     }     pu...
Post a Comment
Read more