Inverse Of An Array

1. You are given a number n, representing the size of array a.
2. You are given n numbers, representing elements of array a.
3. You are required to calculate the inverse of array a.

For definition and constraints check this link
https://www.pepcoding.com/resources/online-java-foundation/getting-started/inverse-of-a-number/ojquestion
The only difference is the range of values is from 0 to n - 1, instead of 1 to n.

Input Format

Input is managed for you

Output Format

Output is managed for you 

Constraints

0 <= n < 10^7

For more constraints check this

https://www.pepcoding.com/resources/online-java-foundation/getting-started/inverse-of-a-number/ojquestion

The only difference is the range of values is from 0 to n - 1, instead

of 1 to n

Sample Input

5

4

0

2

3

1

Sample Output

1

4

2

3

0

import java.io.*;

import java.util.*;

public class Main{

  public static void display(int[] a){

    StringBuilder sb = new StringBuilder();

    for(int val: a){

      sb.append(val + "\n");

    }

    System.out.println(sb);

  }

  public static int[] inverse(int[] a){

    // write your code here

    int[] res = new int[a.length];

    for(int i=0;i<a.length;i++){

        res[a[i]] = i;

    }

    return res;

  }

public static void main(String[] args) throws Exception {

    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

    int n = Integer.parseInt(br.readLine());

    int[] a = new int[n];

    for(int i = 0; i < n; i++){

       a[i] = Integer.parseInt(br.readLine());

    }

    int[] inv = inverse(a);

    display(inv);

 }

}