Skip to main content

Duplicate Brackets

 1. You are given a string exp representing an expression.

2. Assume that the expression is balanced  i.e. the opening and closing brackets match with each other.

3. But, some of the pair of brackets maybe extra/needless. 

4. You are required to print true if you detect extra brackets and false otherwise.

e.g.'

((a + b) + (c + d)) -> false

(a + b) + ((c + d)) -> true

Input Format

A string str

Output Format

true or false

Constraints

0 <= str.length <= 100

Sample Input

(a + b) + ((c + d))

Sample Output

true


Solution:
import java.io.*;
import java.util.*;

public class Main {

    public static void main(String[] args) throws Exception {
        Scanner sc =new Scanner(System.in);
        String str = sc.nextLine();
        Stack<Character> s = new Stack<>();
        int n = str.length();
        boolean flag = false;
        for(int i=0;i<n;i++){
            char ch = str.charAt(i);
            if(ch == ')'){
                if(s.peek() == '('){
                    flag = true;
                    break;
                }
                while(s.peek() != '(')
                    s.pop();
                s.pop();
            }else 
                s.push(ch);
        }
        System.out.println(flag);
    }

}
Labels:

Comments

Post a Comment

Popular posts from this blog

Classes and Objects | Accenture TFA

  Question  1 Correct Mark 1.00 out of 1.00 Flag question Question text ___ and _____ are the access specifiers that can be applied to top level Class. Select one or more: public   protected default   private Feedback Your answer is correct. The correct answers are: default, public Question  2 Correct Mark 1.00 out of 1.00 Flag question Question text class Sample{      private double num = 100;    private int square(int a){ return a*a;    } }   public class Test{    public static void main(String args[]){   Sample obj = new Sample();   System.out.println(obj.num);  System.out.println(obj.square(10));    }   } Select one: Compile time error   Run time error Executes but no output 100 Feedback Your answer is correct. The correct answer is: Compile time error Question  3 Correct Mark 1.00 out of 1.00 Flag question Question text Choose the appropriate access specifier for the attribute value so that it can be accessed from anywhere. class Test { Choose... private protected public d
Post a Comment
Read more

Classes and Objects, Packages | Accenture TFA

  Question  1 Correct Mark 1.00 out of 1.00 Flag question Question text State True or False When using eclipse whichever classes are needed for the present class can be imported automatically. Select one: True   False Feedback The correct answer is 'True'. Question  2 Correct Mark 1.00 out of 1.00 Flag question Question text switch(a) {     default:         System.out.println("Welcome"); } Of which data types can the variable ‘a’ be? 1. long 2. byte 3. int 4. char 5. float 6. short Select one: 3, 4 and 5 1 and 3 3 and 4 2,3, 4 and 6   Feedback Your answer is correct. The variable used in a switch statement can be a byte, short, int, char or String type only. The correct answer is:  2,3, 4 and 6 Question  3 Correct Mark 1.00 out of 1.00 Flag question Question text Predict the output.   public class Test {         public static void main(String args[])         {                     int a = 2, b = 0;              for ( ; b < 20; ++b) {                  if (b % a == 0)
Post a Comment
Read more

Balanced Brackets

1. You are given a string exp representing an expression. 2. You are required to check if the expression is balanced i.e. closing brackets and opening brackets match up well. e.g. [(a + b) + {(c + d) * (e / f)}] -> true [(a + b) + {(c + d) * (e / f)]} -> false [(a + b) + {(c + d) * (e / f)} -> false ([(a + b) + {(c + d) * (e / f)}] -> false Input Format A string str Output Format true or false Constraints 0 <= str.length <= 100 Sample Input [(a + b) + {(c + d) * (e / f)}] Sample Output true Solution import java.io.*; import java.util.*; public class Main {     public static void main(String[] args) throws Exception {         Scanner sc = new Scanner(System.in);         String str = sc.nextLine();         int n = str.length();         Stack<Character> s = new Stack<>();         for(int i=0;i<n;i++){             char ch = str.charAt(i);             if(ch == '[')                 s.push(']');             else if(ch == '{'
Post a Comment
Read more