Skip to main content

JEE Main Counselling & Procedure 2019

JEE Main Counselling 2019: Only candidates securing qualifying marks in JEE Main will be eligible to participate in the counselling process. The seat allotment process will take place in June 2019. Check JEE Main 2019 Cutoff


What is JEE Main Seat Allocation Process?

  • The Seat Allotment Process is purely based on the merit and the choices made by candidates in JoSAA and CSAB.
  • Once the allotted seat is rejected, candidates will not be allowed to participate in the further rounds of the counselling.
  • After the JoSAA seat allotment, CSAB counselling will take place.


What is the procedure for JEE Mains 2019 Counselling?



The procedure of JEE Main Counselling & Seat Allotment 2019

Follow the mentioned below steps to participate in JEE Main 2019 counselling and seat allotment:
Step 1 – Online Registration
To participate in JEE Main 2019 counselling and seat allotment, candidates will have to register to JoSAAin online mode by entering roll number and password.
Step 2 - Online Choice Filling & Locking
Fill and lock the choices in order of the preference of colleges and B.Tech programmes. Based on the choices filled seat allotment will be done.
Step 3 – Seat Allotment
Based on the availability of seats, merit and preference entered, candidates, will be allotted seats. However, before the actual seat allotment, mock allotment will be done in two rounds. This will allow candidates to know the seat allotment process and also enable them to know and choose better preferences for themselves in the main rounds.
Step 4 – Payment of Fee & Seat Acceptance
Once the seat is allotted, candidates will have to choose any one of the following options :
Freeze– If candidates are satisfied with the seat allotted to them and do not wish to participate in further rounds, they will have to choose this option.
Float– In case, candidates need to keep the seat allotted and also wish to upgrade their seat, they must follow this option.
Slide– If candidates accept the seat allotted and wish to upgrade the course in the same institute, they will have to stick to this option.
Withdraw– If candidates have already accepted the seat, they can withdraw the seat by reporting at the institute allotted before the last round of seat allotment.
To confirm the seat, candidates will have to pay the fees through SBI Net Banking or e-Challan. The seat acceptance fee (SAF) is Rs 45,000 for all the candidates except SC/ ST/ SC-PwD/ ST-PWD/ GEN-PwD/ OBC-NCL-PwD. Candidates who belong to SC/ ST/ SC-PwD/ ST-PwD/ GEN-PwD/ OBC-NCL-PwD categories will have to pay Rs. 20,000 as SAF.


Step 5 – Verification of Documents
Candidates will have to get their documents verified at the help centres. The following documents need to be produced at the time of verification:

  • 3 passport size photographs (the same as uploaded during registration)
  • Provisional JoSAA seat allotment letter
  • Photo identity card
  • Proof of seat acceptance fee payment
  • JEE Main 2019 Admit Card
  • Date of birth proof
  • JEE Main 2019 Score Card
  • Class XII Mark sheet
  • Category certificate (if applicable)


Step 6 – Final Reporting at the Allotted Institute
Once verification is done, candidates will have to report at the allotted institute and pay the balance fees in the institute, confirm the admission.



Labels:

Comments

Post a Comment

Popular posts from this blog

Classes and Objects | Accenture TFA

  Question  1 Correct Mark 1.00 out of 1.00 Flag question Question text ___ and _____ are the access specifiers that can be applied to top level Class. Select one or more: public   protected default   private Feedback Your answer is correct. The correct answers are: default, public Question  2 Correct Mark 1.00 out of 1.00 Flag question Question text class Sample{      private double num = 100;    private int square(int a){ return a*a;    } }   public class Test{    public static void main(String args[]){   Sample obj = new Sample();   System.out.println(obj.num);  System.out.println(obj.square(10));    }   } Select one: Compile time error   Run time error Executes but no output 100 Feedback Your answer is correct. The correct answer is: Compile time error Question  3 Correct Mark 1.00 out of 1.00 Flag question Question text Choose the appropriate access specifier for the attribute value so that it can be accessed from anywhere. class Test { Choose... private protected public d
Post a Comment
Read more

Classes and Objects, Packages | Accenture TFA

  Question  1 Correct Mark 1.00 out of 1.00 Flag question Question text State True or False When using eclipse whichever classes are needed for the present class can be imported automatically. Select one: True   False Feedback The correct answer is 'True'. Question  2 Correct Mark 1.00 out of 1.00 Flag question Question text switch(a) {     default:         System.out.println("Welcome"); } Of which data types can the variable ‘a’ be? 1. long 2. byte 3. int 4. char 5. float 6. short Select one: 3, 4 and 5 1 and 3 3 and 4 2,3, 4 and 6   Feedback Your answer is correct. The variable used in a switch statement can be a byte, short, int, char or String type only. The correct answer is:  2,3, 4 and 6 Question  3 Correct Mark 1.00 out of 1.00 Flag question Question text Predict the output.   public class Test {         public static void main(String args[])         {                     int a = 2, b = 0;              for ( ; b < 20; ++b) {                  if (b % a == 0)
Post a Comment
Read more

Balanced Brackets

1. You are given a string exp representing an expression. 2. You are required to check if the expression is balanced i.e. closing brackets and opening brackets match up well. e.g. [(a + b) + {(c + d) * (e / f)}] -> true [(a + b) + {(c + d) * (e / f)]} -> false [(a + b) + {(c + d) * (e / f)} -> false ([(a + b) + {(c + d) * (e / f)}] -> false Input Format A string str Output Format true or false Constraints 0 <= str.length <= 100 Sample Input [(a + b) + {(c + d) * (e / f)}] Sample Output true Solution import java.io.*; import java.util.*; public class Main {     public static void main(String[] args) throws Exception {         Scanner sc = new Scanner(System.in);         String str = sc.nextLine();         int n = str.length();         Stack<Character> s = new Stack<>();         for(int i=0;i<n;i++){             char ch = str.charAt(i);             if(ch == '[')                 s.push(']');             else if(ch == '{'
Post a Comment
Read more