Spiral Display

 1. You are given a number n, representing the number of rows.

2. You are given a number m, representing the number of columns.
3. You are given n*m numbers, representing elements of 2d array a.
4. You are required to traverse and print the contents of the 2d array in form of a spiral.
Note - Please check the sample output for details.

Input Format

A number n
A number m
e11
e12..
e21
e22..
.. n * m number of elements

Output Format

e11
e21
..
en1
en2
en3
..
enm
e(n-1)m
..
e1m
e1(m-1)
..
e12
e22
e32
..

Constraints
1 <= n <= 10^2
1 <= m <= 10^2
-10^9 <= e1, e2, .. n * m elements <= 10^9
Sample Input
3
5
11
12
13
14
15
21
22
23
24
25
31
32
33
34
35
Sample Output
11
21
31
32
33
34
35
25
15
14
13
12
22
23
24

import java.io.*;
import java.util.*;

public class Main {

    public static void main(String[] args) throws Exception {
        // write your code here
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int m = sc.nextInt();
        int[][] A = new int[n][m];
        
        for(int i=0;i<n;i++)
            for(int j=0;j<m;j++)
                A[i][j] = sc.nextInt();
        
        int minRow = 0, minCol = 0, maxRow = n-1, maxCol = m-1, totalEle = n*m,count = 0;
        while(totalEle > count){
            for(int i=minRow;i<=maxRow && count < totalEle;i++){
                System.out.println(A[i][minCol]);
                ++count;
            }
            ++minCol;
            
            for(int i=minCol;i<=maxCol && count < totalEle;i++){
                System.out.println(A[maxRow][i]);
                ++count;
            }
            --maxRow;
            
            for(int i=maxRow;i>=minRow && count < totalEle;i--){
                System.out.println(A[i][maxCol]);
                ++count;
            }
            --maxCol;
            
            for(int i=maxCol;i>=minCol && count < totalEle;i--){
                System.out.println(A[minRow][i]);
                ++count;
            }
            ++minRow;
        }
    }

}